+2A ROMs 0 - 3 on 2x Eprom
Posted: Mon Jun 22, 2020 5:22 pm
Just to verify before I burn the ROMs.... the Spectrum +2A/+2B/+3 physically have 2x 32k ROM chips, usually referred to as A and B. I know that they consist of 4 banks of 16k ROM data.
Am I right in thinking that ROM A contains 16k ROMs 0 and 1 (with 0 starting at the beginning and 1 in the 2nd half) and that for ROM B it's the same principle, with the first 16k space taken up by ROM 2 and the last 16k being ROM 3?
Thanks.
Am I right in thinking that ROM A contains 16k ROMs 0 and 1 (with 0 starting at the beginning and 1 in the 2nd half) and that for ROM B it's the same principle, with the first 16k space taken up by ROM 2 and the last 16k being ROM 3?
Thanks.