Sinclair ZX80 / ZX81 / Z88 Forums

I have at the moment no means to test it (my dev environment is broken), but the following program should be able to fully load 1008 bytes into memory (from 0x4000 to 0x4400 - 16 bytes)... The block to be load should be saved with standard routines and should be equal or bigger than 1008 bytes (if ...

I took off 1 table and now memory will be enough to code the game.

At this moment I only need to add the AI of the computer

The comments say that I can use #4000 to #400B for variables, but the org starts at #4009. Would I start it at #4000 if I wanted to make use of that RAM? Would I leave the rest of this snippet alone for my own game? I assume I could at least use the two bytes with the mem label after initialization...

What I was afraid for just happened....

OUT OF MEMORY in 1K.

I am working on solving it but it might end in cutting of a table so @dmitrii, last one added, might lose the table.

I had hoped to have a small loader that would allow loading more data in a 1K machine. Now bound on around 949 bytes.
Alas, this routine is way too large to have use in 1K. My optimized model is more effective on a 1K model.

This is an interesting thread. Is a long time that I was thinking that in order to fully (at least to the maximum extent) utilize the 1K memory it would be good to have a extremely small piece of code that (also reusing the standard load routines) could load programs. It means that first you would ...

So I am coding my next 1K game for the ZX81. The following persons claimed a country for the game. ; Land Inhabitant ; Netherlands Raymond Wiggers ; Ireland Darren Branagh ; England Gary Hawes ; Wales Laucsap Noslohcin ; France Poulette73 ; USA John C Stroebel ; Germany Jens ; Spain Salvacam ; Portu...

Just 2.5 years ago, i'd vote for russian and R , because i am russian ...Absolutely not sure now :roll: In the original boardgame the russians are a part too and I don't blaim the russian people for a dictators obsession. S for Sweden would do (because i've grown up in Stockholm, Lidingö, and my ZX...

The short answer: RTFM The polite answer: ATTR(Y,X) returns the setting of the colours on that field. So when your last printed character there is a different INK or PAPER then you will get that in return with something like LET A=ATTR(Y,X) SCREEN$(Y,X) can return the printed character there but onl...

Lardo Boffin wrote: ↑Thu Apr 11, 2024 8:17 pm It’s in my basket. Just waiting on adding enough other stuff to get free delivery.

You are entitled a free signed copy from me for your review work.
I need to order a few myself including 1 for you.